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## The new pH away from a sample away from white vinegar is 3

The new pH away from a sample away from white vinegar is 3

Question 13. 76. Calculate the concentration of hydrogen ion in it. Answer: pH = – logten [H3O + ] = – log10 = – pH = – 3.76 = $$\overline$$.dos4 [H3O + ] = antilog $$\overline<4>$$.24 = l.738 x 10 -4 [H3O + ] = 1.74.x 10 -4 M

Question 14. The ionisation constant of HF, HCOOH McAllen escort reviews, HCN at 298 K are 6.8 x 10 -4 , 1.8 x 10 -4 and 4.8 x 10 -9 respectively. Calculate the ionisation constant of the corresponding conjugate base. Answer: 1. HF, conjugate base is F Kb = Kw/Ka = $$\frac<1>><6.8>>$$ = l.47 x 10 -11 = l.5 x 10 -11

Concern fifteen. New pH away from 0.1 M services regarding cyanic acidic (HCNO) are dos.34. Assess the new ionization lingering of your acidic as well as amount of ionization regarding solution. HCNO $$\rightleftharpoons$$ H + + CNO – pH = 2.34 function – record [H + ] = dos.34 otherwise journal [H + ] = – 2.34 = step three.86 or [H + ] = Antilog step three.86 = cuatro.57 x ten -3 Yards [CNO – ] = [H + ] = 4.57 x 10 -3 Yards

Question 16. The Ionization constant of nitrous acid is 4.5 x 10 -4 . Calculate the pH of 0.04 M sodium nitrite solution and also its degree of hydrolysis. Answer: Sodium mtrite is a salt of weak acid, strong base. Hence, Kh = 2.22 x 10-11 Kw/Kb = 10 -14 /(4.5x 10 -4 )

[OH – ] = ch = 0.04 x 2.thirty-six x 10 -5 = 944 x ten -eight pOH = – log (9.44 x ten -seven ) = 7 – 0.9750 = six.03 pH = 14 – pOH = fourteen – six.03 = seven.97

Question 17. What is the minimum volume of water required to dissolve 1 g of calcium sulphate at 298K.Read More »The new pH away from a sample away from white vinegar is 3