# Move volume inside the L so you can frequency into the mL therefore, the equipment to possess thickness (g mL -step one ) would be uniform:

Move volume inside the L so you can frequency into the mL therefore, the equipment to possess thickness (g mL -step one ) would be uniform:

(ii) Have you made use of the correct number of extreme rates? density (step one.03 ) have 3 significant figures frequency (1) has 1 extreme shape Whenever multiplying or splitting, just how many tall numbers regarding the outcome is the same just like the the very least amount of extreme figures in the words used, so we was warranted in making use of step one tall contour. Our very own respond to (ten30) keeps cuatro tall figures! Given that we have been merely warranted in using step one tall profile, we are able to allow the answer since the a lot of g, nevertheless the best answer is to try to play with medical notation and you can write 1 ? 10 step three g

(iii) Will be your respond to possible? Perform a “rough” calculation: thickness ≈ step one grams mL -step 1 step 1 mL off dairy features quite a few regarding step one grams step one L (one thousand mL) regarding milk has actually quite a few regarding the 1000 ? step one = a lot of grams Since this rough formula is close to the new very carefully determined value having mass the audience is relatively positive that the respond to is right.

Matter 5. In the 25°C and you can 1 automatic teller machine pressure, diamond have a density of step 3.5 g cm -3 . Estimate the volume from inside the cm 3 of 0.fifty grams from diamond within 25°C and you can step one atm pressure.

3.5 g cm -step 3 ? V (cm step 3 ) = V(cm step three ) ? 0.fifty grams ? V (cm 3 ) 3.5 grams cm -step three ? V (cm 3 ) = 0.50 g

[ step three.5 grams cm -step three ? V (cm step 3 )] ? step 3.5 g cm -step three = 0.50 g ? step 3.5 g cm -step 3 V (cm 3 ) = 0.50 ? step 3.5 (cm -3 ) = 0.14 cm step three

## Manage a beneficial “rough” calculation: density ≈ 5 grams cm -step 3 step one cm -step three off diamond has actually scores of on 5 grams

(ii) Maybe you have made use of the proper number of extreme figures? occurrence (step 3.5) features 2 significant figures regularity (0.50) keeps 2 tall data Whenever multiplying otherwise dividing, the amount of extreme rates on the result is the same given that least level of tall data throughout the words used, therefore we try warranted in making use of dos high numbers. The answer (0.14) possess 2 significant data

(iii) Is your answer plausible? 50 g for the mass which is 1 /10 th the mass of 1 cm -3 of diamond So the volume of 0.50 g of diamond will 1 /10 th the volume that is V = 1 /10 ? 1 cm 3 = 0.1 cm 3 Since this “rough” answer Tyler escort is about the same as our carefully calculated answer we are reasonably confident that our answer is correct.

Question six. At the twenty five°C and you can 1 automatic teller machine stress, ethylene glycol enjoys a density of 1.11 g mL -step 1 . Assess the quantity in mL away from 0.025 kilogram off ethylene glycol from the twenty five°C and you will 1 automatic teller machine pressure.

Move size within the kg in order to bulk into the grams to help you be consistent which have gadgets of occurrence (g mL -1 ):

V (mL) ? step 1.eleven (g mL -step one ) = V (mL) ? twenty-five (g) ? V (mL) V (mL) ? 1.eleven (grams mL -step one ) = twenty five (g)

## The question provides 0

[V (mL) ? step 1.eleven (g mL -step 1 ) ] ? step one.eleven (g mL -1 ) = twenty five (g) ? 1.11 ( g mL -1 ) V (mL) = twenty five ? 1.eleven (mL -step one ) = 23 mL

(ii) Have you utilized the proper amount of tall figures? mass (0.025) has actually dos high data thickness (step one.11) has step three significant numbers Whenever multiplying or isolating, the number of high rates regarding result is the same since the the very least amount of tall rates in the terms and conditions utilized, therefore we is actually warranted in using 2 significant numbers. Our answer (25) has actually 2 significant figures